Json string with image url or Json format encoding for url

Question

This is how I'm getting result while I'm trying to encode string in JSON format. I want that url should be in this: http://ipaddress/Up/user_images/549279.jpg

RESULT:

{"result":[{"id":"42","name":"http://IPADDRESS/Up/user_images/380289.jpg"},{"id":"43","name":"http://IPADDRESS/Up/user_images/995062.jpg"},{"id":"44","name":"http://IPADDRESS/Up/user_images/171544.jpg"},{"id":"41","name":"http://IPADDRESS/Up/user_images/549279.jpg"}]}

Warning: json_decode() expects parameter 1 to be string, array given in C:\xampp\htdocs\jsn\PHP_Scripts\getAllEmp.php on line 26

//creating a blank array 
$result = array();
$r1 = array();

//looping through all the records fetched
while ($row = mysqli_fetch_array($r)){
    //Pushing name and id in the blank array created 
    array_push($result,array(
        "id"=>$row['userID'],
        "name"=>$ur.$row['userPic'],
    ));
} 

//Displaying the array in json format 
echo json_encode(array('result'=>$result));
$r1= json_decode($result, true);
echo ($r1);
//  echo json_decode(array("result"=>$r1));

mysqli_close($con);

stackoverflow.com/questions/4319105/… refer this, it will help — Anjali
– Anjali, Commented Jan 23, 2017 at 6:02

Nishant Nair · Accepted Answer · 2017-01-23 06:00:44Z

0

try below code

    //creating a blank array 
    $result = array();
    $r1=array();
    //looping through all the records fetched
    while($row = mysqli_fetch_array($r)){
        //Pushing name and id in the blank array created 
            array_push($result,array(
            "id"=>$row['userID'],
            "name"=>$ur.$row['userPic'],
        ));
    } 
    //Displaying the array in json format 
    $jsonData =  json_encode($result);
    echo $jsonData;  // **MODIFIED LINE**
    $r1 = json_decode($jsonData, true); // **MODIFIED LINE**
    print_r($r1);
    mysqli_close($con);

answered Jan 23, 2017 at 6:00

Nishant Nair

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2 Comments

Vinny Over a year ago

We are not getting the result in JSON format. We are getting the same result as before and rtrim also not working

Vinny Over a year ago

Thank you for your replay,I have found the answer '$jsonData = json_encode($result,JSON_UNESCAPED_SLASHES); echo $jsonData;'

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