Convert a binary string into an array of integers in swift 3

Question

I tried to converting a string into an array, but its showing error

var boolean = "01101010101001010111"

i tried to spilt the string by characters it didn't worked and tried to convert it into array.

resultArray = [0,1,1,0,1,0,1,0,1,0,1,0,0,1,0,1,0,1,1,1]

My code attempt

boolean = "01101010101001010111"
let componentsArray =  boolean.components(separatedBy: .controlCharacters) 

resultArray = Array(componentsArray) as! [Int]

And the error

Error: Generic parameter "Element could not be inferred"

What did you try and what error did you get? What result do you expect for the string "0-X/1Y€🤡"? — Martin R
– Martin R, Commented Jan 24, 2017 at 6:42
@Joe let resultArray = boolean.characters.flatMap{Int(String($0))} — Leo Dabus
– Leo Dabus, Commented Jan 24, 2017 at 6:47

Martin R · Accepted Answer · 2020-03-15 18:23:31Z

4

A possible solution (now updated for Swift 4 and later):

let zeroOneString = "01101010101001010111"

let resultArray = zeroOneString.compactMap { char in
    char == "0" ? 0 : char == "1" ? 1 : nil
}

print(resultArray) // [0, 1, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 0, 1, 0, 1, 0, 1, 1, 1]

zeroOneString.compactMap maps the sequences of all characters in the string. The closure maps "0" to 0 and "1" to 1. Everything else is mapped to nil and ignored by compactMap.

edited Mar 15, 2020 at 18:23

answered Jan 24, 2017 at 6:49

Martin R

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1 Comment

Lindemann Over a year ago

Swift 5 Update: let array = str.compactMap { $0 == "0" ? 0 : 1}

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