I'd like to accomplish something like
{
char st[30] = "This is number %d", 1;
printf("%s", sentence);
}
But obviously it doesn't work...
EDIT: Fixed title
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2 Answers
You're going to have to do the formatting separately from the initialization.
char st[30];
snprintf(st, sizeof st, "This is number %d", i);
printf("%s\n", st);
This is not an "array of strings"; it's a single string by the way. If you really wanted to do an array (as the i implies) you'd have to put the above in a loop:
char st[20][30];
for(int i = 0; i < 20; ++i)
{
snprintf(st[i], sizeof st[i], "This is number %d", i);
}
Then you can print them:
for(int i = 0; i < 20; ++i)
{
printf("%s\n", st[i]);
}
Comments
char st[30];// this is the datatype, array name and size.
//then you have to give values to the array indexes.
st[1]="This is number:";
//for numbers use number data types int, float etc..
//e.g.
int number = 10;
//and then print
printf("%c ", st[1]);
printf("%i", number);