Python string extraction and stripping

Question

I have this string - E1(05): 12 13 16 18 24 E2(01):13 - and all i wish back is:

the contents after the E1 i.e 05,
the list of the 5 numbers i.e. 06 08 12 18 29,
the contents after the E2 i.e. 01,
and lastly, the last number i.e. 13.

I have tried the 're' function but it returns hex string and cannot find examples to strip/split this out with success. There MUST be an elegant way of solving this.

from this example, what i understand is , you just need all numbers from string, right ? — Jay Parikh
– Jay Parikh, Commented Jan 25, 2017 at 13:14
"...the list of the 5 numbers i.e. 06 08 12 18 29" Where did you get these numbers from? — Tagc
– Tagc, Commented Jan 25, 2017 at 13:16
what should be matched from this E1(05): 12 13 16 18 24 E2(01):13 input: [05, 01] ? — RomanPerekhrest
– RomanPerekhrest, Commented Jan 25, 2017 at 13:16

Kasravnd · Accepted Answer · 2017-01-25 13:17:56Z

2

Here is one way using re.findall() by using word boundaries around \d+ (in order to not match 1 in E1, etc):

In [9]: s = "E1(05): 12 13 16 18 24 E2(01):13"

In [10]: re.findall(r'\b\d+\b', s)
Out[10]: ['05', '12', '13', '16', '18', '24', '01', '13']

answered Jan 25, 2017 at 13:17

Kasravnd

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Jay Parikh · Accepted Answer · 2017-01-25 13:21:50Z

0

You can do following

data = re.findall(r'\b\d+\b','YOUR_STRING')
ans = [int(i) for i in data]

Hope this helps !

edited Jan 25, 2017 at 13:21

answered Jan 25, 2017 at 13:18

Jay Parikh

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3 Comments

Tagc Over a year ago

This doesn't work. ans is [1, 5, 12, 13, 16, 18, 24, 2, 1, 13]

Jay Parikh Over a year ago

You just need \b to filterout those E1 stuff. Sorry i didn't recognize at first

Tagc Over a year ago

Right, but now your answer is essentially a duplicate of Kasramvd's. The only difference is that you explicitly convert the matches to integers, and it's unclear if that's what OP wants.

BPL · Accepted Answer · 2017-01-25 13:40:04Z

0

Considering you want to get the id of that E token and the information after that, here's a simple solution:

import re

data = "   E1(05): 12 13 16 18 24 E2(01):13 "

for v in data.split("E"):
    if v.strip() == '':
        continue

    m = re.match(r'E.*?\((.*?)\):(.*)', 'E' + v)
    e_id, e_data = m.group(1), [int(v) for v in m.group(2).split()]
    print(e_id, e_data)

Then you'd get something like this:

('05', [12, 13, 16, 18, 24])
('01', [13])

answered Jan 25, 2017 at 13:40

BPL

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