I am asked to do the perl program to find a value(from user input) in array. If matched "its ok". If not matched, then check within the value in the index[0] to index[1] ... index[n]. So then if the value matched to the between two elements then report which is near to these elements might be index[0] or index[1].
Let you explain.
Given array : 10 15 20 25 30;
Get the value from user : 14 (eg.)
Hence 14 matched with in the two elements that is 10(array[0]) - 15(array[1])
Ultimately the check point is do not use more than one
forloop and never use thewhileloop. You need to check oneforloop and many ofifconditions.
I got the output by which I did here is:
use strict;
use warnings;
my @arr1 = qw(10 15 20 25 30);
my $in = <STDIN>;
chomp($in);
if(grep /$in/, @arr1)
{ } #print "S: $in\n"; }
else
{
for(my $i=0; $i<scalar(@arr1); $i++)
{
my $j = $i + 1;
if($in > $arr1[$i] && $in < $arr1[$j])
{
#print "SN: $arr1[$i]\t$arr1[$j]\n";
my ($inc, $dec) = "0";
my $chk1 = $arr1[$i] + 1;
AGAIN1:
if($in == $chk1)
{ }
else
{ $chk1++; $inc++; goto AGAIN1; }
my $chk2 = $arr1[$j] - 1;
AGAIN2:
if($in == $chk2){ }
else
{ $chk2--; $dec++; goto AGAIN2; }
if($inc > $dec)
{ print "Matched value nearest to $arr1[$j]\n"; }
elsif($inc < $dec)
{ print "Matched value nearest to $arr1[$i]\n"; }
}
}
}
However my question is there a way in algorithm?. Hence if someone can help on this one and it would be appreciated.
Thanks in advance.
ltandgtinstead of<and>?forloop or anifcondition with an empty block. I also doubt if the question intends you to avoidwhileloops by constructing them out of labels andgoto.