Pythonic way of finding regex match

Question

I want to extract first name from email address. The email format is <first_name>@gmail.com. If email is not matched return None. I've written the following python code

def getFirstName(email):
    email_re = re.compile(r'(\w+)@gmail.com')
    match = email_re.search(email)
    if match == None:
        return None
    return match.group(1)

The None checking part looks ugly. Can someone suggest better pythonic way of doing it?

if match: return match.group(1) will work. No other explicit returns are needed. — DYZ
– DYZ, Commented Jan 29, 2017 at 0:21
@PeterWood Nope. There is no need to return None: any python function always implicitly returns None if there are no explicit returns. — DYZ
– DYZ, Commented Jan 29, 2017 at 0:24
The code isn't the same as yours. It's checking match is not None before calling group on it, otherwise it's returning None. This is using Python's ternary operator. Also, explicit is better than implicit. — Open AI - Opting Out
– Open AI - Opting Out, Commented Jan 29, 2017 at 0:26

Harald Nordgren · Accepted Answer · 2017-01-29 00:21:55Z

1

This is the Pythonic way of handling this. Well almost.

if match is None

answered Jan 29, 2017 at 0:21

Harald Nordgren

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1 Comment

Sumanth Over a year ago

Agreed. But, I was looking for an something other than if statement. Something like with statement.

Community · Accepted Answer · 2017-05-23 12:33:28Z

0

def get_first_name(email):
    match = re.search(r'(\w+)@gmail\.com', email)
    return match.group(1) if match else None

You need to escape the . in your pattern or else it'll match anything.
The with statement is not relevant here.

edited May 23, 2017 at 12:33

CommunityBot

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answered Jan 30, 2017 at 16:11

ryugie

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