converting an element of an array to a separate String

Question

So I have this problem where I can't convert an element of my array to a string

I have a string like this

var description:[String] =["blue","yellow","red"]

and I want to give one element of my array to another variable which is chosen by another integer like this

var pick:[Int] = 2 var chosen:[String] = description[pick]

it says Cannot assign value of type 'String' to type '[String]' and to fix it xcode suggests to do it like this

var chosen:[String] = [description[pick]]

now if I want to cast this variable to another one or give it to a function or whatever it will say Cannot assign value of type 'String' to type '[[String]]' please help.

Is required for variable chosen to be an array? Otherwise you could just: var chosen: String = description[pick] — Mago Nicolas Palacios
– Mago Nicolas Palacios, Commented Jan 29, 2017 at 14:07

Fogmeister · Accepted Answer · 2017-01-29 14:13:18Z

1

You are getting very confused here...

First...

var array = ["red", "yellow"]

Is an array of strings. Don't call it description. Call things what they are.

Second...

var pick: [Int]

Is declaring an array. Setting it = 2 doesn't make sense.

Change your last line to...

var chosen: String = array[pick]

In the above line using [String] here is telling the system that you are getting an array of Strings. You're not. You're getting a String here.

answered Jan 29, 2017 at 14:13

Fogmeister

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3 Comments

N9va Over a year ago

i was just making an example , like making a integer like carrot or etc but thanks i was just wrong with making chosen an array instead of string and mago helped me realize it thanks anyway.

Fogmeister Over a year ago

@N9va ok. I still don't really know what you're trying to do. There are more problems with your code than just the string array.

N9va Over a year ago

well its in a class which is a object that has couple of traits and I choose between them and create different entities with int pick and int pick is random but it was not really necessary to type it all here so I just presented the bit that was confusing me.

Mago Nicolas Palacios · Accepted Answer · 2017-01-29 14:17:37Z

0

Is required for variable chosen to be an array? Otherwise you could just:

var chosen: String = description[pick]

answered Jan 29, 2017 at 14:17

Mago Nicolas Palacios

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