A list of original strings:
Originals = ["nice apple", "orange", "pear sweet", "red ape"]
A list of strings to remove:
To_remove = ["nice ", " sweet"]
What I want to achieve is to remove the strings needed to be removed in each elements in the original words
result: ["apple", "orange", "pear", "red ape"]
I do following but it doesn’t produce a good result.
for t in To_remove:
for o in Originals:
print o.replace(t, "")
what would be the right way? Thank you.
Strings are immutable. Hence, none of the methods you can call on a string does an in-place modification. They all return a new string, so you have to reassign the string returned by replace:
for t in To_remove:
for i in range(len(Originals)):
Originals[i] = Originals[i].replace(t, "")
You can check out this question for how to merge the replacement of multiple patterns.
snake case)the return value -- better use the result of the replace operation or something like this, to make clear what you mean.
Because string is immutable, you have to reassign the list element.
for t in To_remove:
for i, o in enumerate(Originals):
Originals[i] = o.replace(t, "")
print Originals
hope this helps.
You are printing the results of the replacement, but do not change the list contents. If you have a closer look on the replace method (for strings(!)), you'll see that you are not only not changing the list but also not changing the strings you are getting for o in Originals. I omit including a working example, since schwobaseggl and thangtn [1] already provide it.
[1] Who was really first? The SO timestamps contradict my personal experience.
Originals = ["nice apple", "orange", "pear sweet", "red ape"]
To_remove = ["nice ", " sweet"]
result = []
for o in Originals:
for t in To_remove:
result.append(o.replace(t, ""))
print result
Is that what you need?
but it doesn’t produce a good result-- What do you see? Please show us!