Why does this code print the ASCII value instead of the character

Question

I thought typecasting to char we do the trick but it just prints ascii values

   String str = JOptionPane.showInputDialog("Enter a word");

   str = str.toUpperCase();
   String temp = "";

   for(int i = 0 ; i < str.length() ; i++)
   {
       temp += (char)str.charAt(i) + 1;
   }

   System.out.println(temp);

I'm pretty sure it's implicit conversion from char to int. You're casting it to a char then adding 1 onto it. Put some brackets in. — byxor
– byxor, Commented Feb 5, 2017 at 7:01
Assuming you're trying shift to the next character, trying using temp += (char) (str.charAt(i) + 1);, which takes the char adds 1 to it (resulting in an int) and then casts the result back to char — MadProgrammer
– MadProgrammer, Commented Feb 5, 2017 at 7:03
Just to demonstrate the point , essentially u are doing something like temp += (int)str.charAt(i) + 1; — sean
– sean, Commented Feb 5, 2017 at 7:06
@sean what do you think the temp contains if str.charAt(i) is 'a'. Although OP wants the next alphabetic character not some int value. — jack jay
– jack jay, Commented Feb 5, 2017 at 7:16

Mithilesh Gupta · Accepted Answer · 2017-02-05 07:07:27Z

1

Your mistake is you are adding integer 1 to char . This will return the ASCII code of the next char.

Change to

temp += (char)(str.charAt(i) +1)

edited Feb 5, 2017 at 7:07

answered Feb 5, 2017 at 7:03

Mithilesh Gupta

2,9401 gold badge21 silver badges18 bronze badges

Sign up to request clarification or add additional context in comments.

2 Comments

MadProgrammer Over a year ago

Correct, but why, I'd be nice to provide some background information to the OP so they understand better their mistake and not fall into the same trap again

jack jay Over a year ago

these "change to" kind of things should be comment if they are short enough.

U X · Accepted Answer · 2017-02-05 07:05:29Z

1

You are adding + 1 and that is causing it to be converted to integer I am not sure if explained properly just remove it

answered Feb 5, 2017 at 7:05

U X

1211 gold badge1 silver badge6 bronze badges

1 Comment

Darragh Over a year ago

Sorry i forgot to mention in my question that i was trying to print the next char, but thanks for your answer

Collectives™ on Stack Overflow

Why does this code print the ASCII value instead of the character

2 Answers 2

2 Comments

1 Comment

Your Answer

Linked

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

2 Comments

1 Comment

Your Answer

Sign up or log in

Post as a guest

Linked

Related