How do I replace one element in an array with potentially multiple elements?

Question

I want to replace an item in an array:

arr = ["55", "4.ARTHUR", "masddf"]

with potentially multiple items based on whether it matches a regular expression. I would like to have the result:

["55", "4.", "ARTHUR", "masddf"]

I tried:

arr.map { |o| o =~ /\d+\./ ? o.split(/^(\d+\.)/).reject { |c| c.empty? } : o }
# => ["55", ["4.", "ARTHUR"], "masddf"]

arr.map { |o| o =~ /\d+\./ ? o.split(/^(\d+\.)/).reject { |c| c.empty? }.flatten : o }
# => ["55", ["4.", "ARTHUR"], "masddf"]

I can't seem to get the elements outside of the array they got split into. Any ideas?

Jordan Running · Accepted Answer · 2017-02-06 22:56:28Z

3

Use flat_map instead:

arr = ["55", "4.ARTHUR", "masddf"]
arr.flat_map { |o| o =~ /\d+\./ ? o.split(/^(\d+\.)/).reject { |c| c.empty? } : o }
# => ["55", "4.", "ARTHUR", "masddf"]

See it on repl.it: https://repl.it/F90V

By the way, a simpler way to solve this problem is to use String#scan:

arr.flat_map {|o| o.scan(/^\d+\.|.+/) }

See it on repl.it: https://repl.it/F90V/1

edited Feb 6, 2017 at 22:56

answered Feb 6, 2017 at 22:50

Jordan Running

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