PHP Missing Function In Older Version

Question

My this PHP function converts a datetime string into more readable way to represent passed date and time. This is working perfect in PHP version 5.3.0 but on the server side it is PHP version 5.2.17 which lacks this function. Is there a way I can fix this efficiently? This is not only a function which needs this "diff" function but there are many more.

public function ago($dt1)
 {
  $interval = date_create('now')->diff(date_create($dt1));
  $suffix = ($interval->invert ? ' ago' : '-');
  if ($v = $interval->y >= 1) return $this->pluralize($interval->y, 'year') . $suffix;
  if ($v = $interval->m >= 1) return $this->pluralize($interval->m, 'month') . $suffix;
  if ($v = $interval->d >= 1) return $this->pluralize($interval->d, 'day') . $suffix;
  if ($v = $interval->h >= 1) return $this->pluralize($interval->h, 'hour') . $suffix;
  if ($v = $interval->i >= 1) return $this->pluralize($interval->i, 'minute') . $suffix;
   return $this->pluralize($interval->s, 'second') . $suffix;
 }

Chuck Burgess · Accepted Answer · 2010-11-20 16:07:44Z

3

The answer can be found in the comment right below the one you found your code in on php.net: http://php.net/manual/en/datetime.diff.php

<?php
function date_diff($date1, $date2) {
    $current = $date1;
    $datetime2 = date_create($date2);
    $count = 0;
    while(date_create($current) < $datetime2){
        $current = gmdate("Y-m-d", strtotime("+1 day", strtotime($current)));
        $count++;
    }
    return $count;
}

echo (date_diff('2010-3-9', '2011-4-10')." days <br \>");
?>

answered Nov 20, 2010 at 16:07

Chuck Burgess

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6 Comments

Gordon Over a year ago

and you can add it to your application with if(!function_exists('date_diff')) { // declare function here } so you wont have to bother which version is on the server.

Umair A. Over a year ago

but I specifically need the function "diff"

Gordon Over a year ago

@Umair See the manual. date_diff is the procedural alias of Date::diff

Umair A. Over a year ago

@Gordon: the function will always output difference of days

Umair A. Over a year ago

@Gordon: Thanks for your efforts. I thought I should write that function myself and I did it. I am answering my own question now.

|

Umair A. · Accepted Answer · 2010-12-25 10:11:35Z

I came to this re-written function which works pretty well.

class DateTimeFormatter
{
    private $now;
    public $invert;
    public $y, $m, $d, $h, $i, $s;

    function DateTimeFormatter()
    {
        $this->now = date_parse(date("Y-m-d H:i:s"));   
    }

    function now()
    {
        $this->now = date_parse(date("Y-m-d H:i:s"));
        return $this->now;
    }

    function diff($dt)
    {
        if (!is_array($dt))
            $dt = date_parse($dt);

        if ($this->now() > $dt)
        {
            $this->invert = 1;
            $this->y = $this->now['year'] - $dt['year'];
            $this->m = $this->now['month'] - $dt['month'];
            $this->d = $this->now['day'] - $dt['day'];
            $this->h = $this->now['hour'] - $dt['hour'];
            $this->i = $this->now['minute'] - $dt['minute'];
            $this->s = $this->now['second'] - $dt['second'];
        }
        else
        {
            $this->invert = 0;
            $this->y = $dt['year'] - $this->now['year'];
            $this->m = $dt['month'] - $this->now['month'];
            $this->d = $dt['day'] - $this->now['day'];
            $this->h = $dt['hour'] - $this->now['hour'];
            $this->i = $dt['minute'] - $this->now['minute'];
            $this->s = $dt['second'] - $this->now['second'];
        }

        return $this;                            
    }

    function ago($datetime)
    {
        $interval = $this->diff($datetime);
        $suffix = ($interval->invert ? ' ago' : '');
        if ($v = $interval->y >= 1) return $this->pluralize($interval->y, 'year') . $suffix;
        if ($v = $interval->m >= 1) return $this->pluralize($interval->m, 'month') . $suffix;
        if ($v = $interval->d >= 1) return $this->pluralize($interval->d, 'day') . $suffix;
        if ($v = $interval->h >= 1) return $this->pluralize($interval->h, 'hour') . $suffix;
        if ($v = $interval->i >= 1) return $this->pluralize($interval->i, 'minute') . $suffix;
        return $this->pluralize($interval->s, 'second') . $suffix;
    }

    function pluralize( $count, $text )
    {
        return $count . (($count == 1) ? (" $text") : (" ${text}s"));
    }
}

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