I have an array:
char[] modifiers = {'A', 'M', 'D'};
and a variable:
char a = 'D'
How to get position of variable value in array?
Thanks
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6 Answers
This is the shortest way I know. I had this as a comment but now writing it as an answer. Cheers!
Character[] array = {'A','B','D'};
Arrays.asList(array).indexOf('D');
2 Comments
Ondrej Sotolar
Well this doesn't work. Try it with the OP's values. It returns -1.
st0le
Great catch. fixed. The initialization will need to be with Character.
Try:
int pos = -1;
for(int i = 0; i < modifiers.length; i++) {
if(modifiers[i] == a) {
pos = i;
break;
}
}
This will get the first occurrence of the value in variable pos, if there are multiple ones, or -1 if not found.
Comments
Something along the lines may do the trick:
Collections.indexOfSubList(Arrays.asList(array), Arrays.asList('D'))
Trying to avoid a manual loop :p
You could do it yourself easily enough, you can use the sort() and binarySearch() methods of the java.util.Arrays class, or you can convert the char [] to a String and use the String.indexOf() method.
answered Nov 20, 2010 at 20:29
President James K. Polk
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1 Comment
Jonik
+1.
new String(modifiers).indexOf('D') is a pretty concise way to do this.This is very simple and tested code for your reference
String[] arrayValue = {"test","test1","test2"};
int position = Arrays.asList(arrayValue).indexOf("test");
position: 0th Position
Comments
Iterate through the array and compare its elements to the variable, return the index, if equals. Return -1 if not found. You might want to consider using any implementation of java.util.List.
