Reading from a Tuple and making a String in Scala

Question

I have a list of Tuple(s) like:

val rez = List((A, B, C, D, E, WrappedArray(F1, F2, F3)), (A2, B2, C2, D2, E2, WrappedArray(F4, F5)))

What I am trying to do is to create a string from each tuple in the list, so that (e.g., for the first tuple):

if(C == "Bob") then "A => (F1 \/ F2 \/ F3)"

The elements in the Tuple are, of course, of different types (in the WrappedArray() are of the same type).

My difficult part is how to make the string like (F1 \/ F2 \/ F3) from the elements within the WrappedArray()?

Thanks for any help.

the second element in the list has a WrappedArray of only two elements (F4, F5).. how should it be handled? — rogue-one
– rogue-one, Commented Feb 23, 2017 at 16:32
@rogue-one, it should become like (F4 \/ F5), as the WrappedArray in my case has a different number of elements. — Avah
– Avah, Commented Feb 23, 2017 at 16:37

rogue-one · Accepted Answer · 2017-02-23 16:40:56Z

2

If I understand your requirement correctly.. the below should work..

val rez = List(("A", "B", "Bob", "D", "E", Array("F1", "F2", "F3")), ("A2", "B2", "Bob", "D2", "E2", Array("F4", "F5")))

val result = rez map {
 case (a, b, c, d, e, array) if(c == "Bob") => s"$a => ${array.mkString(" \\/ ")}"
}
result: List[String] = List(A => F1 \/ F2 \/ F3, A2 => F4 \/ F5)

answered Feb 23, 2017 at 16:40

rogue-one

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1 Comment

Avah Over a year ago

"Yes, Sir!" It's really working. I tried so much, in different ways :(. Thank you so much!

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