Start python file in Swift

Question

I want to start a pythonscript by pushing a Button in a swift macOS application. I come up with:

let process = Process()
process.launchPath = "/usr/bin/python3"
process.currentDirectoryPath = "\(NSHomeDirectory())" + "/PycharmProjects/untitled5"
process.arguments = ["myscript.py"]
process.launch()

but I get "launch path not accessible" error by executing. If I change launchPath to:

process.launchPath = "/usr/bin/python"

everything works fine, but now I getting python compiling errors because myscript is written in python3.6.0, I have to use python3 because of using a library. When I open Finder and go to "/usr/bin/python3" it says not found, but python3 is installed, I used it in Pycharm and I'm also able to start python3 in terminal. In terminal "python3 ~/PycharmProjects/untitled5/myscript.py" works.

What does which python3 say? Are you sure, that it points to "/usr/bin/python3"? — Nathan Mattes
– Nathan Mattes, Commented Mar 5, 2017 at 15:07

user7662097 · Accepted Answer · 2017-03-05 15:06:38Z

1

On your terminal type

which python3

this will return the path that is accessed when you run python3 from the command line

answered Mar 5, 2017 at 15:06

user7662097

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