Finding a regular expression in java

Question

I have a String in java that is actually a JSON object. Inside the string I am trying to find a pattern matching this

"uris" : ["www.google.com", "www.yahoo.com"]

I need help in creating a pattern string to find a match for this. I have no idea of automata theory and regular expressions.

Note: the above substring will always start at "uris" and end at "]" but there can be any number of spaces in between.

what's wrong with calling YourJsonObject.getJSONArray("uris"); and traverse the array using loop etc — Pavneet_Singh
– Pavneet_Singh, Commented Mar 10, 2017 at 17:19
the content should be always a url like your do, or it can be any thing? — Youcef LAIDANI
– Youcef LAIDANI, Commented Mar 10, 2017 at 17:19
Why not use proper JSON parser? You would avoid many potential problems like handling keys which only ends with uris, or searching within values of other keys like key="foo uris: [something]". — Pshemo
– Pshemo, Commented Mar 10, 2017 at 17:22

m87 · Accepted Answer · 2017-03-10 17:16:19Z

2

You may use the following regex :

"uris".*?\]

see regex demo / explanation

Java ( demo )

import java.util.regex.Matcher;
import java.util.regex.Pattern;

class RegEx {
    public static void main(String[] args) {
        String s = "\"uris\" : [\"www.google.com\", \"www.yahoo.com\"]";
        String r = "\"uris\".*?\\]";
        Pattern p = Pattern.compile(r);
        Matcher m = p.matcher(s);
        while (m.find()) {
            System.out.println(m.group()); //"uris" : ["www.google.com", "www.yahoo.com"]
        }
    }
}

answered Mar 10, 2017 at 17:16

m87

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