Spring @Value TypeMismatchException:Failed to convert value of type 'java.lang.String' to required type 'java.lang.Double'

Question

I want to use the @Value annotation to inject a Double property such as:

@Service
public class MyService {

    @Value("${item.priceFactor}")
    private Double priceFactor = 0.1;

// ...

and using Spring property placeholder (Properties files):

item.priceFactor=0.1

I get Exception:

org.springframework.beans.TypeMismatchException: Failed to convert value of type 'java.lang.String' to required type 'java.lang.Double'; nested exception is java.lang.NumberFormatException: For input string: "${item.priceFactor}"

Is there a way to use a Double value coming from a properties file?

is double works?

Ami Hollander
– Ami Hollander

2017-03-11 08:52:27 +00:00
Commented Mar 11, 2017 at 8:52 — Ami Hollander
– Ami Hollander, Commented Mar 11, 2017 at 8:52
@AmiHollander it fails even for primitive type double

guilhebl
– guilhebl

2017-03-11 08:57:20 +00:00
Commented Mar 11, 2017 at 8:57 — guilhebl
– guilhebl, Commented Mar 11, 2017 at 8:57

bcr666 · Accepted Answer · 2017-03-11 13:08:50Z

84

Try changing the following line

@Value("${item.priceFactor}")

to

@Value("#{new Double('${item.priceFactor}')}")

answered Mar 11, 2017 at 13:08

bcr666

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2 Comments

ArifMustafa Over a year ago

one million price answer, very rare and not available in many places

realPK Over a year ago

Works like a charm on Spring boot 1.5.9

alex.b · Accepted Answer · 2019-12-03 13:54:30Z

8

This should solve the problem-

@Value("#{T(Double).parseDouble('${item.priceFactor}')}")
private Double priceFactor;

edited Dec 3, 2019 at 13:54

alex.b

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answered Mar 11, 2017 at 11:26

pkoli

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2 Comments

Joe Over a year ago

int is primitive.. Try the object Integer

alegria Over a year ago

I was able to make this work with a primitive Long, and I think this should be a part of the accepted answer since addition of T(Double) instead of Double is the real catch here and hard to be found intuitively. Thank you for this answer.

Omar YAYA · Accepted Answer · 2021-05-20 00:24:17Z

1

I had a similar problem but instead of required type 'java.lang.Double' it was required type 'java.lang.Long'. I was using env. variables from a YAML file. Turns out YAML doesn't support the Long data type.

answered May 20, 2021 at 0:24

Omar YAYA

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Comments

Coder17 · Accepted Answer · 2022-06-27 14:46:38Z

1

Below logic works for me without using new Double:

@Value("${item.priceFactor}")
private Double priceFactor;

item.priceFactor=0.1

Spring will automatically convert for you.

answered Jun 27, 2022 at 14:46

Coder17

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Comments

Bojan Antonović · Accepted Answer · 2021-12-20 12:35:00Z

0

You forgot the @PropertySource annotation with the name of the properties file as parameter.

It should come before or after your @Service annotation.

Please have a look for a working solution with @Configuration (the super type of @Service) at https://github.com/bojanantonovic/spring-properties-demo.

edited Dec 20, 2021 at 12:35

answered Dec 20, 2021 at 12:27

Bojan Antonović

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Comments

Vitali Pom · Accepted Answer · 2017-03-11 11:10:36Z

-2

How about storing a String and converting to numbers like integers and doubles through getters and setters? For safe code with Java injection you should always use getters and setters and only for other methods in any case. I advice you warmly to read about java security (Which is NOT for hackers), but more for code usage and writing likewise the one you uploaded, wich uses injection.

edited Mar 11, 2017 at 11:10

answered Mar 11, 2017 at 11:01

Vitali Pom

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