In Python 2.7.x, I've created an Exception class:
class myException(RuntimeError):
def __init__(self,arg):
self.args = arg
When I use it:
try:
raise myException("This is a test")
except myException as e:
print e
It prints out like this:
('T', 'h', 'i', 's', ' ', 'i', 's'...)
I didn't print the whole thing but why isn't this printing out as a string? And how do I convert it?
Also, why is e.message blank?
args on an exception is special; it expects to be a sequence. Assigning a string to self.args is legal, it is a sequence, but it is converted to a tuple when you do.
Assign a tuple containing your argument instead:
class myException(RuntimeError):
def __init__(self, arg):
self.args = (arg,)
See the BaseException documentation:
args
The tuple of arguments given to the exception constructor. Some built-in exceptions (likeIOError) expect a certain number of arguments and assign a special meaning to the elements of this tuple, while others are usually called only with a single string giving an error message.
All you have to do is:
class myException(RuntimeError):
def __init__(self,arg):
self.args = (arg,)
def __init__(self,*arg):(note the star)?