How to load file from resources directory in Java

Question

I am trying to load a properties file directly from the resources directory of my Java project and am getting a null pointer exception. Can someone pl explain how to do it?

Code-

String resourceName = "config-values.properties"; 
Properties props = new Properties();
try(InputStream resourceStream = getClass().getClassLoader().getResourceAsStream(resourceName)) {
            props.load(resourceStream);
        }

My folder structure is - /src/packageName and /src/resources/

Did you use maven to generate the project skeleton, if so can you confirm that you dir structure should be src/main/java AND src/main/resources. Otherwise, you may just need to use path as "resources/config-values.properties" in getResourceAsStream — jatanp
– jatanp, Commented Mar 14, 2017 at 6:50
The structure is not src/main/resources just src/resources @jatanp what do you mean by "need to use path as resources/config-values.properties"? — AP01
– AP01, Commented Mar 14, 2017 at 6:54

HRVHackers · Accepted Answer · 2020-04-07 04:13:20Z

3

Adding another way to do it without stream

File ourFile = new File(getClass().getClassLoader().getResource("yourFile.txt").getFile());

and then you can do things like

ourFile.getAbsolutePath()

answered Apr 7, 2020 at 4:13

HRVHackers

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Community · Accepted Answer · 2017-05-23 12:25:48Z

2

Following code expects that the resource, you are trying to access, exists in your class path.

getClassLoader().getResourceAsStream(resourceName))

Assuming that your file exists in src/resources: You may add src/resources/ in your classpath. I don't know which IDE are you using but here are some ways to add a directory in the classpath:

Intelli J : how to add directory to classpath in an application run profile in intellij idea?
Eclipse : How do I add a directory to the eclipse classpath?
At run time : Can a directory be added to the class path at runtime?
At command line : http://javarevisited.blogspot.com/2012/10/5-ways-to-add-multiple-jar-to-classpath-java.html

edited May 23, 2017 at 12:25

CommunityBot

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answered Mar 14, 2017 at 7:18

user2241537

Comments

Sagar Gangwal · Accepted Answer · 2017-03-14 06:52:35Z

1

InputStream resourceStream  = 
 getClass().getResourceAsStream("/package/folder/foo.properties");

Try above code.

Hope this will helps.

answered Mar 14, 2017 at 6:52

Sagar Gangwal

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