How do I create an org.xml.sax.InputSource from a String?

Question

I am following a guide, and it gives me the following code:

InputSource inputSource = new InputSource(new FileInputStream(new File("/path/to/xml/file.xml"))));

What I would like to know, is how I can still create an org.xml.sax.InputSource, but instead of reading the content of a file, use a String variable that I already have.

Oskar Birkne · Accepted Answer · 2014-01-03 08:39:23Z

104

Use a StringReader instead of a FileInputStream.

See the documentation for StringReader

example:

InputSource inputSource = new InputSource( new StringReader( myString ) );

edited Jan 3, 2014 at 8:39

Oskar Birkne

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answered Nov 25, 2010 at 20:53

Gavin H

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khachik · Accepted Answer · 2010-11-25 20:55:31Z

4

InputSource inputSource = new InputSource(new java.io.StringReader(string)); if it is org.xml.sax.InputSource.

answered Nov 25, 2010 at 20:55

khachik

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