I want to convert "5565.80" to 5565.80 and "5565.00" to 5565.00. The issue with to_f is that it removes the last 0 when the 2 decimals are .00. Is there a single way to do both?
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2 Answers
Float
You can convert "5565.80" to a float :
value = "5565.80".to_f
# 5565.8
And then display the value with two decimals :
'%.2f' % value
# "5565.80"
A float has double-precision in Ruby, so your value will actually be :
5565.800000000000181898940354...
As a float, you cannot save exactly 5565.80.
Exact values
Integer
If you want exact values (e.g. for currency), you could use integers for cents :
"5565.80".delete('.').to_i
# 556580
When you need the corresponding float, you could divide it by 100.0.
Decimal
If you're working with a database, you could use decimal(20,2) or something equivalent.
BigDecimal
You could also use BigDecimal :
require 'bigdecimal'
BigDecimal.new("5565.80")
It will save the exact value but will be much slower than int or float.
3 Comments
Ilya
So, the answer is NO :)
Eric Duminil
@Ilya The answer is "YES, BUT".
Ilya
I think the question is about converting a string to float with double zero in the end.
You can use #round.
The argument to round is how many decimals you want to round to. Some examples:
5565.80.round(2) # => 5565.8 # omits trailing 0's
5565.00.round(2) # => 5565.0 # only keeps the decimal to show that this is a float
5565.79.round(2) # => 5565.79 # rounds to two digits
5565.123.round(3) # => 5565.123 # rounds to three decimal places, so nothing is lost
5565.123.round(2) # => 5565.12 # drops the 3
5565.129.round(2) # => 5565.13 # drops the 9 and rounds up
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