If I've got an XML file like this:
<root
xmlns:a="http://example.com/a"
xmlns:b="http://example.com/b"
xmlns:c="http://example.com/c"
xmlns="http://example.com/base">
...
</root>
How can I get a list of the namespace definitions (ie, the xmlns:a="…", etc)?
Using:
import xml.etree.ElementTree as ET
tree = ET.parse('foo.xml')
root = tree.getroot()
print root.attrib()
Shows an empty attribute dictionary.
Via @mzjn, in the comments, here's how to do it with stock ElementTree: https://stackoverflow.com/a/42372404/407651 :
import xml.etree.ElementTree as ET
my_namespaces = dict([
node for (_, node) in ET.iterparse('file.xml', events=['start-ns'])
])
You might find it easier to use lxml.
from lxml import etree
xml_data = '<root xmlns:a="http://example.com/a" xmlns:b="http://example.com/b" xmlns:c="http://example.com/c" xmlns="http://example.com/base"></root>'
root_node = etree.fromstring(xml_data)
print root_node.nsmap
This outputs
{None: 'http://example.com/base',
'a': 'http://example.com/a',
'b': 'http://example.com/b',
'c': 'http://example.com/c'}
