Shell script curl REST API - quoting issues

Question

curl -X DELETE -d '{"ruleid": "${value}"}' 'http://192.168.0.12:8080/wm/firewall/rules/json'

This command can't run correctly. I don't know how to handle this value parameter. How to use the quotes?

#! /bin/bash
#  delete a firewall rule
value=x
if [ $1 != "" ]; then
value=$1
echo "$value"
curl -X DELETE -d '{"ruleid": "${value}"}'     http://192.168.0.12:8080/wm/firewall/rules/json
exit 0

else
    echo "no parameter "
    exit 0
fi

A helpful post here: Difference between single and double quotes in Bash — codeforester
– codeforester, Commented Mar 24, 2017 at 16:17

user000001 · Accepted Answer · 2017-03-24 16:11:22Z

3

This example is a nightmare of quoting, but here is the correct syntax:

  curl -X DELETE -d '{"ruleid": "'"$value"'"}'
#                                ||      |
# here we close the single quote +|      + the same applies for closing 
#                                 |
#      here we open double quotes +

You should enclose everything in single quotes, except for the variable that is double quoted.

An alternative would be

curl -X DELETE -d "{\"ruleid\": \"$value\"}"

answered Mar 24, 2017 at 16:11

user000001

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