Javascript - If loop skipping code inside, if the condition refers to an array

Question

In example 1, running that results in line 4 being executed and then skipping right over line 5. In example 2, changing line 4 to refer to the actual value rather than an array allows line 5 to be executed.

What can I do to make example 1 work properly? And why does example 2 work and not example 1?

I've used the same for loop in another instance, with a different array, that worked perfectly. So perhaps it's the array itself that's the problem?

1.

var temp2 = rightbarcoderead(i);

        for (i = 0; i < 10; i++) {
            if (temp2 === righteven[i]) {
                rightbarcode += i
            }

2.

var temp2 = "100110";

        for (i = 0; i < 10; i++) {
            if (temp2 === righteven[i]) {
                rightbarcode += i
            }

What does rightbarcoderead(i) return you (try console.log(temp2))? Why are you using i there and then again for the for loop? Why do you think the array is the issue here? Couldn't you just replace this whole loop with righteven.indexOf(temp2)? — gen_Eric
– gen_Eric, Commented Mar 27, 2017 at 16:02

Paolo · Accepted Answer · 2017-03-27 16:10:18Z

1

From the information provided the only thing we know for sure is that in example 1 temp2 is not set with the expected value 100110.

This may be due to i being undefined when you call

var temp2 = rightbarcoderead(i);

or i set with the wrong value or, again, rightbarcoderead() function not returning the expected result with the given i parameter.

edited Mar 27, 2017 at 16:10

answered Mar 27, 2017 at 16:04

Paolo

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