How to run a function repeatedly with a fixed delay using Python?

Question

I have a function f()that I want to run from time to time, let's say each 10 seconds. My goal is to run it indefinitely, only being killed by a interrupt. I looked into the sched module, but couldn't find how to run the function repeatedly ad infinitum. Maybe a while True loop?

I think you just need the time module with time.sleep(10) in a while True loop, unless your requirement is more complicated than you have explained in the question. Note that this will give a 10 second pause after each function call, but will not take into account how long the function itself takes to execute. — roganjosh
– roganjosh, Commented Mar 28, 2017 at 19:06
I would you a loop, with sleep function, e.g. from time import sleep sleep(0.1) # Time in seconds — Vadim
– Vadim, Commented Mar 28, 2017 at 19:07

spicypumpkin · Accepted Answer · 2017-03-28 19:14:42Z

1

import time

while True:
    f()
    time.sleep(10)

Try it!

answered Mar 28, 2017 at 19:14

spicypumpkin

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