PHP: Need to convert imagemagick command to php script

Question

I use this command to batch modify images for a site. They need to be this size to suit the theme.

Now I also want to use these images in Facebook Ads, but they have to be resized. The command I use (which works fine) is:

for i in `ls -1 *.jpg`; do convert $i -fuzz 10% -trim +repage -resize 980x1200 -background white -gravity center -extent 980x1200 $i; done

Now I need to make a PHP script that does the same, but also returns the image as response.

I came up with the following:

<?php

/* Create the object and read the image in */
$im = new Imagick("image.jpg");

/* Trim the image with 10% fuzz */
$im->trimImage(10);

/* Repage */
$im->setImagePage(0, 0, 0, 0);

/* Resize */
$im->resizeImage(1200,628,Imagick::FILTER_LANCZOS,0);

/* Add Borders*/
$im->setImageBackgroundColor('White');
$im->setGravity('Centre');
$im->setImageExtent(1200,628);

/* Output the image */
header("Content-Type: image/" . $im->getImageFormat());
echo $im;
?>

Unfortunately it doesn't seem to work. All it does is return a black rectangle (which looks like the right dimensions as used in the script).

You cannot simply echo $im. You should use echo $im->getimageblob();. — KIKO Software
– KIKO Software, Commented Mar 30, 2017 at 22:34
Both my echo and yours seem to work for me. Unfortunately it just returns a black rectangle in the correct dimensions. So I assume something is going wrong in the manipulations — johnny538
– johnny538, Commented Mar 31, 2017 at 18:24

miken32 · Accepted Answer · 2017-03-30 23:00:58Z

1

First error I get when running this code:

PHP Warning: Imagick::setgravity() expects parameter 1 to be integer, string given in resize.php on line 18

Try using imagick::GRAVITY_CENTER instead.

Next issue, Imagick::resizeImage() and Imagick::setImageExtent() expect parameters in width, height order.

Finally, try setting a non-zero value like 1 for blur on Imagick::resizeImage() to resolve the black image issue.

I'm not sure how you are trying to get a border, but you may want to look at Imagick::borderImage().

I don't know if that will solve all your problems, but it should get you a lot closer!

<?php

/* Create the object and read the image in */
$im = new Imagick("image.jpg");

/* Trim the image with 10% fuzz */
$im->trimImage(10);

/* Repage */
$im->setImagePage(0, 0, 0, 0);

/* Resize */
$im->resizeImage(628, 1200, Imagick::FILTER_LANCZOS, 1);

/* Add Borders*/
$im->setImageBackgroundColor('White');
$im->setGravity(Imagick::GRAVITY_CENTER);
$im->setImageExtent(628, 1200);

/* Output the image */
header("Content-Type: image/" . $im->getImageFormat());
echo $im;
?>

edited Mar 30, 2017 at 23:00

answered Mar 30, 2017 at 22:55

miken32

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10 Comments

johnny538 Over a year ago

setGravity(Imagick::GRAVITY_CENTER) doesn't seem to change anything. It still errors on expecting an int

miken32 Over a year ago

Imagick::GRAVITY_CENTER is an integer. If it's not, you'd be getting other errors.

miken32 Over a year ago

And you never did answer the question about ImageMagick version.

johnny538 Over a year ago

ImageMagick 6.8.9-9 Q16 x86_64 2017-03-12

johnny538 Over a year ago

Actually, after restarting apache2, I get no errors. But it's still not working.

|

Gopinath · Accepted Answer · 2017-03-31 05:44:14Z

0

you can run commands in php using " shell_exec(your command) ". Try once this may works for you. Refer http://php.net/manual/en/function.shell-exec.php

answered Mar 31, 2017 at 5:44

Gopinath

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