I have to write regex that checks if string:
I appreciate any help because I am really stuck on this and don't have any ideas how to solve this.
You can use look ahead to check all conditions, and then match 5 to 15 characters (any), making sure there is nothing else (^ and $):
^(?=(?:.*[A-Z]){2})(?=(?:.*[a-z]){2})(?=.*\d).{5,15}$
^: start of string (?= ): positive look ahead. Does not grab any characters, but just looks ahead to see if the pattern would be matched(?: ): make this group non-capturing, i.e. you'll not get it as capturing group that you can reference with $1 or \1 (language dependent).*[A-Z]: 0 or more character(s) followed by a capital letter.*[a-z]: 0 or more character(s) followed by a lower case letter.*\d: 0 or more character(s) followed by a digit{2}: previous pattern must match twice.{5-15}: 5 to 15 characters.$: end of stringIn JavaScript you can test a string against a regular expression with test, for example:
var regex = /^(?=(?:.*[A-Z]){2})(?=(?:.*[a-z]){2})(?=.*\d).{5,15}$/;
console.log(regex.test('a9B1c')); // false, missing capital letter
console.log(regex.test('a9B1cD')); // true
trinctot was right first, but depending on who is using your code and for what, this might be easier to maintain/modify:
var lowerPass = 2 <= (string.match(/[a-z]/g) || []).length;
var upperPass = 2 <= (string.match(/[A-Z]/g) || []).length;
var digitPass = 1 <= (string.match(/[0-9]/g) || []).length;
var lengthPass = 5 <= string.length <= 15;
var stringPass = lowerPass + upperPass + digitPass + lengthPass == 4;
Try this
^([a-z]{2,}[A-Z]{2, }[0-9]{1}+) {5, 15}$
