How to declare array in method [duplicate]

Question

I am currently having to write a method that takes in two parameters: an array of integers called data and an integer called num. The purpose of this method is to count the amount of times that number shows up in the array. I am having trouble figuring out how to declare the array in the method. I was wondering if there was any easier way that I did below:

Method

public static void countNumbers( int data[], int num ) {
        int count = 0;

        for(int i = 0; i < data.length; i++) {
            if(data[i] == num)
                count++;
        }
        if (count == 0)
            System.out.println("There are no " + num + "'s in the array.");
        if (count == 1)
            System.out.println("There is one " + num + " in the array.");
        if (count > 1)
            System.out.println("There are: " + count + " " + num + "'s in the array.");
}

Main Class

public static void main(String args[]) {
        int firstArray[] = {1,2,3,4,5};
        Methods.countNumbers(firstArray, 2);
    }

So I was wondering if you could directly declare the array within the countNumbers(data,num) any help would be appreciated!

I don't understand your question -- you declare the array in the method parameter and appear to do so appropriately. So what is this all about? What confuses you. — Hovercraft Full Of Eels
– Hovercraft Full Of Eels, Commented Apr 7, 2017 at 1:05
I was wondering if there was any way to declare the array within the method such as: Methods.countNumbers(int firstArray[] = {1,2,3} , 2); — Mason Salcido
– Mason Salcido, Commented Apr 7, 2017 at 1:07
If you don't reference it anywhere else (you don't need it anywhere else) just do Methods.countNumbers({1, 2, 3}, 2) — MCMastery
– MCMastery, Commented Apr 7, 2017 at 1:13

domsson · Accepted Answer · 2017-04-07 01:07:43Z

3

Is that what you are looking for?

public static void main(String args[]) {
    Methods.countNumbers(new int[] {1,2,3,4,5}, 2);
}

answered Apr 7, 2017 at 1:07

domsson

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2 Comments

Mason Salcido Over a year ago

This was exactly what I was looking for, thank you very much. I can not accept an answer just yet though!

domsson Over a year ago

Ha, glad I could be of help. And don't worry, you can always come back once you've got more rep. :)

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