Scala way for converting Long to ArrayByte

Question

I'm trying to convert the Long to array byte. This code block is working but this solution is a Java solution. I'm looking for a good solution in Scala. How can I convert the Long to array byte in Scala way?

val arrayByteFromLong: Array[Byte] = ByteBuffer.allocate(8).putLong(myLong).array()

It's perfectly fine for Scala too (I'd prefer it to Federico's answer). One exception is if you are looking for code which will work in Scala.js/Scala Native. — Alexey Romanov
– Alexey Romanov, Commented Apr 8, 2017 at 13:07

Federico Pellegatta · Accepted Answer · 2017-04-08 12:14:51Z

5

You can leverage scala.math.BigInt:

import scala.math.BigInt

val arrayByteFromLong: Array[Byte] = BigInt(myLong).toByteArray

If you want to also pad the array to 8 Bytes you can do (quick-and-dirty not so efficient version):

arrayByteFromLong.reverse.padTo(8,0).reverse

edited Apr 8, 2017 at 12:14

answered Apr 8, 2017 at 11:52

Federico Pellegatta

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2 Comments

Techmag Over a year ago

Just as easy to get back via BigInt(arrayByteFromLong).toLong

maizy Over a year ago

note that BigInt.toByteArray and ButeBuffer have different padding rules: BigInt(-4227595774L).toByteArray => Array(-1, 4, 4, 2, 2) ByteBuffer.allocate(8).putLong(-4227595774L).array() => Array[Byte] = Array(-1, -1, -1, -1, 4, 4, 2, 2)

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