issues finding number of element in array in c

Question

int input[] = {4, 5, 6, 7, 8};
printf("size of input is %d\n", sizeof(input));

invariably gives me 20 elements!

Any clue why please ?

It's because sizeof(input) will give you the number of elements in the array multiplied by their type size, in this case 4 bytes. If you want to get the number of elements just divide by the size of the type of each element, printf("size of input is %d\n", sizeof(input)/sizeof(int)); — George
– George, Commented Apr 9, 2017 at 0:16

Jayveer Parmar · Accepted Answer · 2017-04-09 00:26:10Z

2

It prints size of array and I think you want number of element in an array. In my computer, int size is 4 bytes. So, total size will be 5*4=20 bytes. If you want number of elements in array, you can write

int input[] = {4, 5, 6, 7, 8};
int n = sizeof(input) / sizeof(input[0]);
printf("number of input is %d\n",n);

answered Apr 9, 2017 at 0:26

Jayveer Parmar

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