I was wondering if there is something similar to Java's JFileChooser for Python?
JFileChooser is a graphical front end to choose a file.
Preferably something that is already with Python. Maybe with Tkinter.
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A quick explanation of what JFileChooser is might help get some better answers.Harley Holcombe– Harley Holcombe2009-01-11 23:07:05 +00:00Commented Jan 11, 2009 at 23:07
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6 Answers
wxPython (www.wxpython.org) provides the wx.FileDialog class which will give you a native file selection dialog on any of the supported platforms (Mac, Linux or Windows).
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Easiest way I ever found to do this (using PyGTK and Kiwi):
from kiwi.ui.dialogs import open as open_dialog
chosen_path = open_dialog('Select a file', folder='/start/folder')
if chosen_path is not None:
# do something ...
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For something that doesn't require wxPython and sticks with the standard Python libs, you can use the tkFileDialog.askopenfilename() method:
#!/usr/bin/python
from Tkinter import *
from tkFileDialog import askopenfilename
root = Tk()
root.withdraw()
print askopenfilename()
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erik
Maybe this worked for python2. But for python3 you need the answer of A. L. Strine.
That would depend on your windowing toolkit. wxWidgets provides the wxFileDialog.
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For python 3 what you're looking for is tkinter.filedialog, and all that comes with it. Here's a short program that opens and then prints a TXT file of the user's choosing via askopenfilename:
from tkinter import *
from tkinter.filedialog import askopenfilename
root = Tk()
root.withdraw()
root.update()
pathString = askopenfilename(filetypes=[("Text files","*.txt")])
if pathString:
openFile = open(pathString, 'r')
fileString = openFile.read()
print(fileString)
root.destroy()
Output is whatever is in the selected file.
1 Comment
erik
For python3 you need to check for definition of
pathString (not for empty string): if pathString: (see this answer stackoverflow.com/a/47067803/1908115 )Maybe you would like to take a look at Jython.
