Don't capture matched part of string with regex in javascript

Question

I am trying to capture part of matched string. Here's what I've done:

var myRegex = /(^[0-9]{2}\.[0-9]{2}\.|$)/;
vary myString = "33.11.999";
var match = myRegex.exec(myString);
console.log(match[1]);

console will output 33.11. but i want to exclude the last dot. Is it possible to do that using regex?

Why do you need to match the end of string? What was your intention? Please add your pattern requirements. — Wiktor Stribiżew
– Wiktor Stribiżew, Commented Apr 13, 2017 at 14:27

kind user · Accepted Answer · 2017-04-13 14:26:43Z

1

You can use positive lookahead (?=), to ignore the last dot.

var myRegex = /(^[0-9]{2}\.[0-9]{2}(?=\.)|$)/;
var myString = "33.11.999";
var match = myRegex.exec(myString);
console.log(match[1]);

answered Apr 13, 2017 at 14:26

kind user

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Comments

Mateo Barahona · Accepted Answer · 2017-04-13 14:32:34Z

1

So why not capture only the part you want ?

var myRegex = /(^[0-9]{2}\.[0-9]{2})\.|$/;
var myString = "33.11.999";
var match = myRegex.exec(myString);
console.log(match[1]);

answered Apr 13, 2017 at 14:32

Mateo Barahona

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Mr.lin · Accepted Answer · 2017-04-13 17:01:33Z

1

var regex=/\d+\.\d+(?=\.\d+)/;
var str='33.11.999';
var result=str.match(regex);
console.info(result[0]);

you can write like this too.

answered Apr 13, 2017 at 17:01

Mr.lin

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