String concatenation in Haskell

Question

My problem is to build a function that given a person and an amount of hours(Integer) it adds "erp" at the start of the name, but the "r" must multiply the amount of hours.

My function must be of the type:

drink :: Integer -> Client -> Client

here it´s an example:

drink 5 (Aperson name _ _) = "errrrrpname"

I know how to do the concatenation but i dont know how to multiply the "r" the amount of time.

Can you make a function that just takes in a String s and an integer n and gives back the String that is s multiplied by n (without dealing with the Client stuff)? I would start there. — David Young
– David Young, Commented Apr 13, 2017 at 16:16
Then why didn't you title your question to reflect the fact that you are interested in "string multiplication" (rather than mere "concatenation")? — metaphori
– metaphori, Commented Apr 13, 2017 at 16:29
If you want to use a standard library function (instead of implementing it yourself), there is replicate. — Lazersmoke
– Lazersmoke, Commented Apr 13, 2017 at 16:31

metaphori · Accepted Answer · 2017-04-13 16:26:43Z

1

Repeating a char

take 10 $ repeat 'a'     -- "aaaaaaaaaa"

Repeating a string

[1..10] >>= (\_ -> "x-") -- "x-x-x-x-x-x-x-x-x-x-"
[1..10] >> "x-"          -- "x-x-x-x-x-x-x-x-x-x-"

answered Apr 13, 2017 at 16:26

metaphori

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2 Comments

Lazersmoke Over a year ago

While both of these work, neither one is really appropriate for what he is doing.

chi Over a year ago

@Lazersmoke I agree on that these are suboptimal, but they work, have the correct complexity, and are reasonably readable. This is a good answer in my eye, and would be very good if only the library didn't contain replicate(M). But that's not a huge deal.

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