I am trying to add 0.10 to 23.50 but I get 23.50.10 instead of 23.60
console.log((parseFloat(23.50) + parseFloat((Math.random() * 0.10) + 0.01).toFixed(2)));
This piece of code generates decimal point like: 0.04, 0.29, etc...
parseFloat((Math.random() * 0.90) + 0.01).toFixed(2)
Your .toFixed is in the wrong parenthesis.
try
console.log((parseFloat(23.50) + parseFloat((Math.random() * 0.10) + 0.01)).toFixed(2));
You have .toFixed(2) in the wrong place. The result of that creates a string which is then being concatenated. It should look like this:
console.log((parseFloat(23.50) + parseFloat((Math.random() * 0.10) + 0.01)).toFixed(2));
Consolidating the comments:
As Scott Sauyet said, toFixed is in the wrong place. You end up with number + string, which converts the number to string and does string concatenation.
As I said: That's not the only problem. You don't parseFloat something that's already a number. Do so converts the number to string, then parses that string as a number, which is at best pointless. :-)
As Barmar said: Do the calculation, then use toFixed on the result:
console.log((23.50 + (Math.random() * 0.10) + 0.01).toFixed(2));
Also, + is lower precedence than *, so you don't need those inner parens (or the last 0 on 0.10):
console.log((23.50 + Math.random() * 0.1 + 0.01).toFixed(2));
...though of course, you could include them for style reasons if you liked.
It may be a typo but your .toFixed() is in the wrong spot. It's translating yourparseFloat((Math.random() * 0.10) + 0.01) to string before the addition to parseFloat(23.50) resulting in string concatenation.
Perform the add and then .toFixed():
console.log((parseFloat(23.50) + parseFloat((Math.random() * 0.10) + 0.01)).toFixed(2));
Or be extra cautious and use a var:
var foo = parseFloat(23.50) + parseFloat((Math.random() * 0.10) + 0.01);
console.log(foo.toFixed(2));
parseFloatsomething that's already a number.toFixed(2)returns a string. Adding that to a number becomes string concatenation.toFixed(2)at the end when you want to show it.parseFloat((Math.random() * 0.10) + 0.01)could it be that you meanMath.floor(Math.random() * 10 + 1) / 100