Numpy converting date object to datetime64[s] in newer version

Question

Why numpy started converting date object to datetime64[s] type object in the newer versions ? How to make it backward compatible ?

Example:

Code snippet:

import datetime
import numpy as np

dt = datetime.date(1970, 1, 1)

array = np.array([dt], dtype='datetime64[s]')

array

Result:

**Numpy version 1.12.0**

array(['1970-01-01T00:00:00'], dtype='datetime64[s]')

**Numpy version 1.9.3**

TypeError: Cannot cast datetime.date object from metadata [D] to [s] according to the rule 'same_kind'

Does this answer help stackoverflow.com/a/37444604/2254228 ? — Chuck
– Chuck, Commented Apr 16, 2017 at 16:15

hpaulj · Accepted Answer · 2017-04-16 16:24:08Z

1

Try a `'D' intermediate:

In [27]: np.array([dt],'datetime64[D]')
Out[27]: array(['1970-01-01'], dtype='datetime64[D]')
In [28]: np.array([dt],'datetime64[D]').astype('datetime64[s]')
Out[28]: array(['1970-01-01T00:00:00'], dtype='datetime64[s]')

Though in my version, the direct creation works:

In [29]: np.array([dt],'datetime64[s]')
Out[29]: array(['1970-01-01T00:00:00'], dtype='datetime64[s]')
In [30]: np.__version__
Out[30]: '1.12.0'
In [31]: dt
Out[31]: datetime.date(1970, 1, 1)

edited Apr 16, 2017 at 16:24

answered Apr 16, 2017 at 16:19

hpaulj

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2 Comments

Sid Over a year ago

Thanks. This works. But then how can I find that the actual unit of dt is 'D' and not 's' ?

Sid Over a year ago

Also, It works in newer version for me too. But I want to check whether dt is datetime64[D] compatible or datetime64[s] compatible ? Like datetime.date(1970, 1, 1) is datetime64[D] type compatible but datetime.datetime(1970, 1, 1, 10, 30) is datetime64[s] type compatible.

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