condition matching in an array with case class in scala

Question

I have a task need to find a particular string in an array: 1. if found, return its value; 2. if not found, return -1.

I wrote an "idea" code, but I don't know how to finish it correctly.

case class person(name:String, value: Int)
personList[Array[person]]

val result = personList match { 
case x if x.name == "john" => x.value
case _ => -1 }

the complier reports errors at "case x if x.name"

If found return value, i.e. String. If not found return -1, i.e. Int. That doesn't sound right. String and Int are different types. — jwvh
– jwvh, Commented Apr 19, 2017 at 1:21

jwvh · Accepted Answer · 2017-04-19 01:32:18Z

1

Would this work for you?

persons.find(_.name == "john").fold(-1)(_.value)

Note: I've left the creation and/or population of the persons array up to you.

answered Apr 19, 2017 at 1:32

jwvh

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Comments

lserlohn · Accepted Answer · 2017-04-19 17:47:51Z

0

val result = personList.find(_.name=="john") match { 
case some(x) => x.value
case None => -1 }

answered Apr 19, 2017 at 17:47

lserlohn

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