PHP: If child array has one value only, replace the array with that value

Question

My question is rather straight forward, yet I am very unsure on how to do it in an effective way.

Say we have an array like this:

array (
    [0] => array(
        [0] => "a"
        )
    [1] => array(
        [0] => "b"
        [1] => "c"
        )
    ["a"] => array(
       ["b"] => "d"
       )
    )

It does not matter to me wether or not keys are preserved, what I ultimately want to end up with is this (with or without key preservation, doesnt matter too much):

Expected output:

array (
    [0] => "a"
    [1] => array(
        [0] => "b"
        [1] => "c"
        )
    ["a"] => "d"
    )

I hope you can help!

~ Troels

mickmackusa · Accepted Answer · 2017-05-17 08:18:08Z

2

Here we are inserting the first value of an array. when count of $value is equal to 1.

Try this code snippet here

<?php
$array=array (
    0 => array(
        0 => "a"
        ),
    1 => array(
        0 => "b",
        1 => "c"
        ),
    "a" => array(
       "b" => "d"
       )
    );
foreach($array as $key => $value)
{
    if(is_array($value) && count($value)==1)
    {
        $array[$key]=current($value); //replace array with lone value
    }
}
print_r($array);

Output:

Array
(
    [0] => a
    [1] => Array
        (
            [0] => b
            [1] => c
        )

    [a] => d
)

edited May 17, 2017 at 8:18

mickmackusa♦

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answered Apr 19, 2017 at 7:15

Sahil Gulati

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2 Comments

lazyCoder Over a year ago

where the php tag questions there will be @Sahil Gulati's answer :D you are too active (y)

Troels M. B. Jensen Over a year ago

Gonna mark your comment as the answer, as you took the fact that the value might not be an array into consideration, something I didnt account for in the example array but no doubt could happen; thank you for the answer

Bhaskar Jain · Accepted Answer · 2017-04-19 07:21:29Z

1

$arr = array (
    0 => array(
        0 => "a"
        ),
    1 => array(
        0 => "b",
        1 => "c"
        ),
    "a" => array(
       "b" => "d"
       )
    );
    echo "<pre>"; print_r($arr);
    foreach($arr as $key=>$val){
        if(is_array($val) && count($val) == 1){
           $arr[$key] = array_shift($val); //get first element of the array which have only one element
        }
    }
      echo "<pre>"; print_r($arr);

PHP Demo

answered Apr 19, 2017 at 7:21

Bhaskar Jain

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2 Comments

Jack Over a year ago

why complicating things with array_shift() instead of a simple $arr[$key] = $val[$key]; ?

Bhaskar Jain Over a year ago

@Jack Good question, please check array and check sub array keys, hope that will clear your doubt. We don't know the key of sub array thats why I used array_shift()

sujivasagam · Accepted Answer · 2017-04-19 07:33:38Z

0

<?php

$temp = array (
    0 => array(
        0 => "a"
        ),
    1 => array(
        0 => "b",
        1 => "c"
        ),
    "a" => array(
       "b" => "d"
       )
    );
    echo "<pre>"; print_r($temp);
     $new_arr = array();

 foreach ($temp as $key => $value) {
    if(count($value)>1)
        $new_arr[$key] = $value;
    else
    {
        $new_arr[$key] = array_shift($value);
    }
 }
 echo '<pre>'; print_r($new_arr);

answered Apr 19, 2017 at 7:33

sujivasagam

1,7671 gold badge14 silver badges26 bronze badges

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