How to form a string using list comprehension?

Question

I am trying to form a string using a list.

If the list only has a single element e.g. l = [10] then the string should be 10.

If there are multiple elements e.g. l = [10,20,30] then the string should be 10,20,30.

I tried but it always appends extra , at the end.

"".join("%s," % x for x in l)

This produces 10, and 10,20,30, for the above lists.

Then throw away the last character of that string with [:-1], i.e. "".join("%s," % x for x in l)[:-1] — Michael H.
– Michael H., Commented Apr 20, 2017 at 6:55

Vadim Landa · Accepted Answer · 2017-04-20 07:31:02Z

11

Just use the following:

','.join(str(n) for n in l)

answered Apr 20, 2017 at 7:31

Vadim Landa

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Gino Mempin Over a year ago

To people reading this and using a different separator character than ,, you can replace that with any other string (ex. '--'.join(...)) or even an empty string (ex. ''.join(..)).

Learning Spirit · Accepted Answer · 2017-04-20 07:21:25Z

1

Here's my solution. I do not know if it satisfies your

str(l)[1:-1]

answered Apr 20, 2017 at 7:21

Learning Spirit

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1 Comment

shrishinde Over a year ago

This will work with some change str(l)[1:-1].replace(" ", "")

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