Variable number of fields in Django URL

Question

I'd like a URL of the form:

... field1/eq/value1/field2/gt/value2/ ...

Where I want to filter the contents of the page in the view function based on an arbitrary number of fields (the names of which are not known in advance).

I've tried:

(r'^((?P<field>\w+)/(?P<op>[a-z]+)/(?P<value>\w+)/)*$', my_view)

But the keyword arguments are filled with the last set of three field/op/value to occur in the URL.

Is there any way that I could populate a list or dictionary based on a variable number of URl fields like this?

Or should I be doing this some completely different way?

S.Lott · Accepted Answer · 2010-12-04 13:25:11Z

6

Don't do this.

Use the query string. ?field,eq,value&field,gt,value will work out much better.

answered Dec 4, 2010 at 13:25

S.Lott

393k83 gold badges521 silver badges791 bronze badges

Sign up to request clarification or add additional context in comments.

Collectives™ on Stack Overflow

Variable number of fields in Django URL

1 Answer 1

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

Comments

Your Answer

Sign up or log in

Post as a guest

Related