Bash calls two bash scripts

Question

I have the following script:

#!/bin/bash

if [ "$EUID" -ne 0 ]
  then
    echo '' 
    echo 'Please run the script as root'
    echo ''
  exit
fi

for run in {1..11}
do
    sudo ./start_ap.sh    
    sleep 10    
    sudo ./tst.sh

done

The problem is that after executing

sudo ./start_ap.sh

the next lines will not be executed, because the line sudo ./start_ap.sh needs CTRL+C to stop and only then next lines will be executed.

However, I want that the sudo ./start_ap.sh will be terminated after sudo ./tst.sh and at next step this will be repeated 11 times.

So far, after execution of sudo ./start_ap.sh, the next lines will not be executed without killing its process.

How can I realize it?

P.S. start_ap.sh starts the hostapd and that's why it needs killing for next executions.

I haven't understood a thing you ask. Maybe the first thing you can try is to not need to C-c start_ap.sh in the first place? — zmo
– zmo, Commented Apr 25, 2017 at 21:58
If you have to run the script as root, why run sudo later? — chepner
– chepner, Commented Apr 25, 2017 at 22:25

chepner · Accepted Answer · 2017-04-25 22:27:28Z

1

You need to run ./start_ap.sh in the background, then kill it after ./tst.sh completes. Note that if you actually run the script as root, there is no need to use sudo inside the script.

for run in {1..11}; do
    ./start_ap.sh & pid=$!
    sleep 10
    ./tst.sh
    kill "$pid"
done

answered Apr 25, 2017 at 22:27

chepner

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2 Comments

Mark Delphi Over a year ago

Thank you for your answer. Unfortunately, it does not kill the process. May be there is a way to find the name of process and kill it. In htop it is possible to filter out the name that can be seen under the command raw. Any ideas?

Gordon Davisson Over a year ago

@MarkDelphi Without more information about start_ap.sh and hostapd and their process structure etc it's really hard to make suggestions.

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