I am trying to plot lots of diagrams, and for each diagram, I want to use a variable to label them. How can I add a variable to plt.title? For example:
import numpy as np
import matplotlib.pyplot as plt
plt.figure(1)
plt.ylabel('y')
plt.xlabel('x')
for t in xrange(50, 61):
plt.title('f model: T=t')
for i in xrange(4, 10):
plt.plot(1.0 / i, i ** 2, 'ro')
plt.legend
plt.show()
In the argument of plt.title(), I want t to be variable changing with the loop.
You can change a value in a string by using %. Documentation can be found here.
For example:
num = 2
print "1 + 1 = %i" % num # i represents an integer
This will output:
1 + 1 = 2
You can also do this with floats and you can choose how many decimal place it will print:
num = 2.000
print "1.000 + 1.000 = %1.3f" % num # f represents a float
gives:
1.000 + 1.000 = 2.000
Using this in your example to update t in the figure title:
plt.figure(1)
plt.ylabel('y')
plt.xlabel('x')
for t in xrange(50,61):
plt.title('f model: T=%i' %t)
for i in xrange(4,10):
plt.plot(1.0/i,i**2,'ro')
plt.legend
plt.show()
You can also just concatenate the title string:
x=1
y=2
plt.title('x= '+str(x)+', y = '+str(y))
will make the title look like
x= 1, y = 2
You can use string formatting.
plt.title('f model: T= {}'.format(t)) orplt.title('f model: T= %d' % (t)) C style printimport matplotlib.pyplot as plt
# Daten
bedarf = 515.85
ist_ohne_urlaub = 435.05
ist_mit_urlaub = 359.05
# 1) Diagramm ohne Urlaub
plt.figure()
plt.bar(["Benötigt", "Vorhanden"], [bedarf, ist_ohne_urlaub])
plt.title("Stundenbedarf vs. Stunden vorhanden (ohne Urlaub)")
plt.ylabel("Stunden pro Woche")
plt.ylim(0, bedarf * 1.1) # etwas Platz oberhalb lassen
plt.text(0, bedarf + 5, f"{bedarf:.2f} h")
plt.text(1, ist_ohne_urlaub + 5, f"{ist_ohne_urlaub:.2f} h")
plt.show()
# 2) Diagramm mit 2 Mitarbeitern im Urlaub
plt.figure()
plt.bar(["Benötigt", "Verfügbar (bei Urlaub)"], [bedarf, ist_mit_urlaub])
plt.title("Stundenbedarf vs. verfügbare Stunden (2 MA im Urlaub)")
plt.ylabel("Stunden pro Woche")
plt.ylim(0, bedarf * 1.1)
plt.text(0, bedarf + 5, f"{bedarf:.2f} h")
plt.text(1, ist_mit_urlaub + 5, f"{ist_mit_urlaub:.2f} h")
plt.show()
