I use the below code to open a javafx fxml file in a different window on a button click event and it works fine. But if I click the same button again while the window opened it will create a duplicate window. Is there a possibly solutions to overcome this problem? Thanks in advance.
Parent parent = FXMLLoader.load(getClass().getResource("FXMLDocument.fxml"));
Stage stage = new Stage(StageStyle.DECORATED);
stage.setTitle("Title");
stage.setScene(new Scene(parent));
stage.show();
I just stumbled upon this old question and figured I might answer it for anyone new to JavaFX or coding in general (I'm bored..).
In the provided code (see below) a new Stage is created every time, meaning that if this is run inside of a method you actually create a new Stage variable every time that the code is run:
Stage stage = new Stage(StageStyle.DECORATED);
What you could do instead create your Stage variable outside the method so that you either 1. just overwrite it every time or 2. have some "is showing" or a nullcheck or similar to see if a new stage should be created or if the existing one just needs to be shown.
For example:
private Stage stage;
private void onOpenNewStageBtnClicked(){
if(stage == null){
Parent parent = FXMLLoader.load(getClass().getResource("FXMLDocument.fxml"));
stage = new Stage(StageStyle.DECORATED);
stage.setTitle("Title");
stage.setScene(new Scene(parent));
}
stage.show();
}
Also, what I usually do is I create a Stage factory to avoid a lot of duplicate code and so that I can break out the creation of the stages and the loading of fxmls to other classes than my controller.
