Ignore instance of recursive function Python 3.x

Question

I haven't found anything near a solution yet, if you could at least give me a clue.. I have this function:

def analizar_consulta(consulta, v):
    print('\ntomar consulta: {}\n'.format(consulta))
    #transformar todas las variables en su contenido
    consulta = transformar_variable(consulta, v)
    if consulta[0] in diccionario_funciones.keys():
        parametros = list(filter(lambda x: not(isinstance(x,list)), consulta[1:]))
        consultas = list(filter( lambda x: isinstance(x,list) , consulta[1:]))
        print('parametros: {}'.format(parametros))
        print('consultas: {}\n'.format(consultas))
        if len(consultas) > 0:
            pasadas = list(map(lambda x: analizar_consulta(x, v), consultas))
            parametros.append(pasadas)
        else:
            return diccionario_funciones[consulta[0]](*parametros)
        return diccionario_funciones[consulta[0]](*parametros)
    else:
        raise Exception('Comando no encontrado')

as it is recursive, sometimes it takes arguments from inside the first parameter as a new parameter for itself in a new instance, but sometimes the first argument of the new parameters is a list, which raise an error on the line 5 (consulta[0]) Is there a way to, if there is a list (which only contain numbers), it just returns it instead of continuing with the rest of the code? Sorry for the code is in Spanish, if you don't understand something I can edit it.

when I try it whit ["comparar", ["PROM", "x"], ">", ["DESV", "y"]] this parameter, it raises the error: TypeError: unhashable type: 'list'

Instead of saying "which raise an error on the line 5" you should say what error it raises. Ideally post the complete error traceback. — Duncan
– Duncan, Commented May 5, 2017 at 14:50

aghast · Accepted Answer · 2017-05-05 14:57:54Z

1

Technically, yes. Add at line 4.5:

c0 = consulta[0]
if isinstance(c0, list) and all(isinstance(i, int) for i in c0):
    return

That having been said, the fact that you don't know what your parameter list contains indicates that there's a design problem in your code. You just called a function to do some kind of transformation on your list:

consulta = transformar_variable(consulta, v)

Why didn't you fix it?

Consider taking a look at the overall code, and asking a different question on SO: "How can I do (whatever it is)?"

answered May 5, 2017 at 14:57

aghast

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