I am able to execute the following, where it uses each member of the list to create a different path:
diagnoses = ['DS','FXS']
path = "Transcripts{dirsep}*{diagnosis}{dirsep}*.txt".format(dirsep=os.sep, diagnosis=diagnoses)
However, the following raises an error:
path = os.path.join('Transcripts',diagnoses,'*.txt')
Can I use os.path.join to get multiple paths?
If what you are looking for is to use os.path.join to create the output
Transcripts/*['DS', 'FXS']/*.txt
you could simply cast your diagnoses list to a string like so.
os.path.join('Transcripts', '*'+str(diagnoses), '*.txt')
You would have to use some kind of iteration, like this list comprehension:
>>> paths = [os.path.join('Transcripts', diagnose, '*.txt') for diagnose in diagnoses]
>>> paths
['Transcripts\\DS\\*.txt', 'Transcripts\\FXS\\*.txt']
* works.* operator works
"Transcripts/*['DS', 'FXS']/*.txt", you could simply cast your diagnoses list to a string. os.path.join('Transcripts', '*'+str(diagnoses), '*.txt')