I seem to be getting a type mismatch error when trying to do something like this:
In new workbook:
A1 B1
5 4
Function Test1() As Integer
Dim rg As Range
Set rg = Test2()
Test1 = rg.Cells(1, 1).Value
End Function
Function Test2() As Range
Dim rg As Range
Set rg = Range("A1:B1")
Test2 = rg
End Function
Adding =Test1() should return 5 but the code seems to terminate when returning a range from test2(). Is it possible to return a range?
A range is an object. Assigning objects requires the use of the SET keyword, and looks like you forgot one in your Test2 function:
Function Test1() As Integer
Dim rg As Range
Set rg = Test2()
Test1 = rg.Cells(1, 1).Value
End Function
Function Test2() As Range
Dim rg As Range
Set rg = Range("A1:B1")
Set Test2 = rg '<-- Don't forget the SET here'
End Function
You can also return a Variant() which represents an array of values. Here is an example for a function that reverses values from a range into a new range:
Public Function ReverseValues(ByRef r_values As Range) As Variant()
Dim i As Integer, j As Integer, N As Integer, M As Integer
Dim y() As Variant
N = r_values.Rows.Count
M = r_values.Columns.Count
y = r_values.value 'copy values from sheet into an array
'y now is a Variant(1 to N, 1 to M)
Dim t as Variant
For i = 1 To N / 2
For j = 1 To M
t = y(i, j)
y(i, j) = y(N - i + 1, j)
y(N - i + 1, j) = t
Next j
Next i
ReverseValues = y
End Function
In the worksheet you have to apply this function as an array formula (with Ctrl-Shift-Enter) with an appropriate number of cells selected. The details of the Swap() function are not important here.
Note that for many rows, this is very efficient. Doing the x = Range.Value and Range.Value = x operations when x is an array and the range contains multiple rows columns is many times faster than doing the operations one by one directly on the cells.
Change last line in Test2 to:
Set Test2 = rg
This also works
Function Test2(Rng As Range) As Range
Set Test2 = Rng
End Function
