Regex delimit the start of a string and the end

Question

I'm been having trouble with regex, which I doesn't understand at all.

I have a string '#anything#that#i#say' and want that the regex detect one word per #, so it will be [#anything, #that, #i, #say]. Need to work with spaces too :(

The closest that I came is [#\w]+, but this only get 1 word and I want separated.

Mostra teu código completo

Otávio Barreto
– Otávio Barreto

2017-05-16 00:56:29 +00:00
Commented May 16, 2017 at 0:56 — Otávio Barreto
– Otávio Barreto, Commented May 16, 2017 at 0:56
you mean spaces before and after '#' sign! right?

DexJ
– DexJ

2017-05-16 05:10:17 +00:00
Commented May 16, 2017 at 5:10 — DexJ
– DexJ, Commented May 16, 2017 at 5:10

Hamms · Accepted Answer · 2017-05-16 01:01:47Z

4

You're close; [#\w] will match anything that is either a # or a word character. But what you want is to match a single # followed by any number of word characters, like this: #\w+ without the brackets

var str = "#anything#that#i#say";
var regexp = /#\w+/gi;
console.log(str.match(regexp));

It's possible to have this deal with spaces as well, but I'd need to see an example of what you mean to tell you how; there are lots of ways that "need to work with spaces" can be interpreted, and I'd rather not guess.

answered May 16, 2017 at 1:01

Hamms

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1 Comment

Samuel Monteiro Over a year ago

Ohh yes, what I mean with spaces is the spaces between hashtags like "# anything #that" i need this to be only two words, without taking the space between. But your answer already made that. Thanks :) and sorry for the late response.

DexJ · Accepted Answer · 2017-05-16 05:09:10Z

0

use expression >>  /#\s*(\w+)/g

\s* : to check if zero or more spaces you have between # and word

This will match 4 word in your string '#anything#that#i#say' even your string is containing space between '#anything# that#i# say'

sample to check: http://www.regextester.com/?fam=97638

edited May 16, 2017 at 5:09

answered May 16, 2017 at 5:03

DexJ

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