When I can add values to the array , Exception occurs. In C# , can i set the values without initializing the array length.
int[] test;
test[0] = 10;
6 Answers
No, if you want a data structure that dynamically grows as you Add items, you will need to use something like List<T>. Arrays are fixed in size.
When you have
int[] test;
you haven't instantiated an array, you've merely declared that test is a variable of type int[]. You need to also instantiate a new array via
int[] test = new int[size];
As long as size is positive then you can safely say
int[0] = 10;
In fact, you can say
int[index] = 10
as long as 0 <= index < size.
Additionally, you can also declare, instantiate and initialize a new array in one statement via
int[] test = new int[] { 1, 2, 3, 4 };
Note that here you do not have to specify the size.
Comments
You can't do that with an array, per se, but you can use a List.
List<int> test = new List<int>();
test.Add(10);
Comments
Only that way
int[] a = {10};
But the length of the array will be 1 after that.
Comments
Try
int[] x = new int[] { 1, 2, 3, 4 };
Comments
you can use this way
string[] words;
words = new List<string>() { "hello","hi" }.ToArray()
1 Comment
starball
It would be nice to give a brief explanation of how this works / how it solves the problem, and how it's different than existing answers.
int[] test = { 10 };orvar test = new[] { 10 };, but otherwise, what you ask for is impossible. Perhaps you want a growable collection such asList<T>?