Difference between array[i][:] and array[i,:]

Question

I'm new to python, so I'm used to use array[i][j] instead of array[i,j]. Today a script I created following a tutorial was not working until I found out that I was using

numpy.dot(P[0][:], Q[:][0])

instead of

numpy.dot(P[0,:], Q[:,0])

For some reason the second one works, while the first one gives me a shape error. The matrixes dimensions are MxK and KxN.

I tried to print both P[0][:] and P[0,:], run id(), type() and P[0][:].shape, but couldn't find a reason to it. Why are these things different?

I'm running it on Jupyter Notebook 4.3.0 and Python 2.7.13.

You may want to read How to Ask and minimal reproducible example. — boardrider
– boardrider, Commented May 17, 2017 at 1:41

MSeifert · Accepted Answer · 2017-05-17 09:52:07Z

6

You should almost always use [i, j] instead of [i][j] when dealing with numpy arrays. In many cases there's no real difference but in your case there is.

Suppose you have an array like this:

>>> import numpy as np
>>> arr = np.arange(16).reshape(4, 4)
>>> arr 
array([[ 0,  1,  2,  3],
       [ 4,  5,  6,  7],
       [ 8,  9, 10, 11],
       [12, 13, 14, 15]])

When you use [:] that's equivalent to a new view, but if you do [1, :] or [:, 1] it means get the second row (column). Roughly speaking it means: index the dimension where you had the number and leave the dimension where you had the : alone:

>>> arr[:]
array([[ 0,  1,  2,  3],
       [ 4,  5,  6,  7],
       [ 8,  9, 10, 11],
       [12, 13, 14, 15]])

>>> arr[:, 1]  #  get the second column
array([ 1,  5,  9, 13])
>>> arr[:][1]  # get a new view of the array, then get the second row
array([4, 5, 6, 7])

This is because [1] is interpreted as [1, ...] (... is the Ellipsis object) and for 2D it's equivalent to [1, :].

That's also the reason why the row indexing still works (because it's the first dimension):

>>> arr[1, :]  # get the second row
array([4, 5, 6, 7])
>>> arr[1][:]  # get the second row, then get a new view of that row
array([4, 5, 6, 7])

edited May 17, 2017 at 9:52

answered May 17, 2017 at 1:55

MSeifert

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1 Comment

hpaulj Over a year ago

[:] is a copy for a list,but not an array. It is rarely useful on the RHS with arrays

hpaulj · Accepted Answer · 2017-05-17 04:36:30Z

x[:] makes a shallow copy of a list, but is virtually useless when x is an array. It makes a new view - same data and shape, but different array object. If that's confusing you need to review some basic numpy docs about views and copies.

In a 2d array such as A[0,:] or A[:, 1:5], : is a kind of place holder, identifying a dimension that will be used as a whole. : is converted by Python interpreter to slice(None,None,None), while start:stop:step produces slice(start, stop, step).

A[0,:], which can be shortened to A[0], means pick the 1st 'row' of A, and all of its 'columns'. The action generalizes to higher dimensions, where names like row and column have less intuitive meanings.

A[:,0] means pick the 0th column, and all the row.

A[0][:] expands to A[0,:][:], and means apply [:] to the result of A[0,:], in effect, just take a view of the 1st row (which is a 1d array).

A[:][0] is not the same as A[:,0]; it's the same as A[0,:]. A[:] is the same as A[:,:] a view of the whole 2d array.

If it helps, I could expand the indexing expressions into calls to A.__getitem__(...). Each set of [] is a separate expansion.

In the expression A[:] = ... the [:] is significant, but that's another topic.

These 2 expressions are equivalent:

numpy.dot(P[0][:], Q[:][0])
numpy.dot(P[0,:], Q[0,:])

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