PHP use directories and links stored in variables

Question

before asking this question i have been looking at these 2 posts but i can't seem to find the answer:

I want to create a simple script that displays images with different links using values stored in variables but my script is not working.

<?php
    $array = array(
      "http://yahoo.com",  
      "http://bing.com",  
    );
    for ($val = 0; $val<2; $val++) {
      $b1 = "<a href='{$array[$val]}' target="_blank"><img src="./$val/1.jpg" alt="image here" title="Title"></a>";
      print $b1;
    }
?>

I apologize in advance, pretty sure it's a really dumb question but i really can't find a solution by myself...

Thanks!

need to escape the double quotes $b1 = "<a href='{$array[$val]}' target=\"_blank\"><img src=\"./$val/1.jpg\" alt=\"image here\" title=\"Title\"></a>"; — JYoThI
– JYoThI, Commented May 17, 2017 at 9:17

Karishma Vaidh · Accepted Answer · 2017-05-17 09:47:53Z

1

try this



     $array = array(
          "http://yahoo.com",  
          "http://bing.com",  
        );
        for ($val = 0; $val";
          print $b1;
        }

answered May 17, 2017 at 9:47

Karishma Vaidh

111 bronze badge

Sign up to request clarification or add additional context in comments.

Comments

Waseem Ahmad · Accepted Answer · 2017-05-17 09:22:28Z

0

try this

    <?php
$array = array(
          "http://yahoo.com",  
          "http://bing.com",  
        );
        for ($val = 0; $val<2; $val++) {
          $b1 = "<a href='{$array[$val]}' target='_blank'><img src='../$val/1.jpg' alt='image here' title='Title'></a>";
          print $b1;
        }
?>

Please replace double quote to sinlge qoute

answered May 17, 2017 at 9:22

Waseem Ahmad

4134 silver badges10 bronze badges

Comments

JYoThI · Accepted Answer · 2017-05-17 09:19:54Z

0

Need to escape the double quotes target=\"_blank\"

 $b1 = "<a href='{$array[$val]}' target=\"_blank\"><img src=\"./$val/1.jpg\" alt=\"image here\" title=\"Title\"></a>";

OR

use single quotes inside the the double quotes like this

$b1 = "<a href='{$array[$val]}' target='_blank'><img src='./$val/1.jpg' alt='image here' title='Title'></a>";

answered May 17, 2017 at 9:19

JYoThI

12.1k1 gold badge13 silver badges26 bronze badges

Collectives™ on Stack Overflow

PHP use directories and links stored in variables

3 Answers 3

Comments

Comments

Comments

Your Answer

Linked

Hot Network Questions

Collectives™ on Stack Overflow

3 Answers 3

Comments

Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Linked

Related