Get the image path in ajax and delete that image in laravel 5.4

Question

I am using laravel 5.4 in my project i displayed my images inside source file in laravel blade it shows the image correctly..

 <div  id="dis_img">
                    @foreach($detail_dir_imgs as $detail_dir_img)
                      <img src="{{ asset($detail_dir_img) }}" height="230" width="200" id="pro_img">
                      <span class="del_proimg">X</span>
                    @endforeach
                  </div>

Now i get the image src attribute inside the del_proimg click function which means i want to delete the image when i click this id and the code inside my click function is

$('.del_proimg').click(function(){
      var img= $('#pro_img').attr("src");
      alert(img);
       $.ajax({
        type: "GET",
        url: '/deleteimg',
        data: {'img':img},
        success: function(data){
          console.log("ajaxdata",data);
        },
        error: function(jqXHR, textStatus, errorThrown) {
          console.log(JSON.stringify(jqXHR));
          console.log("AJAX error: " + textStatus + ' : ' + errorThrown);
        }
      });
    });

When the id is clicked it get the imagepath and pass the data to controller everything worked fine but in my controller when i try to delete the image path it doesnot delete the image and my controller code is

  public function deleteimg(Request $request){
            $img =$request->img;
            @unlink(public_path( $img));
            return Response::json([
              'message' => $request->img
          ], 200);

        }

Is this is correct i tried this also File::delete($img) but its not delete my image in my folder but no error shows please anyone help me to fix this isssue

Maybe file-access rights?

Martin Heralecký
– Martin Heralecký

2017-05-17 13:21:06 +00:00
Commented May 17, 2017 at 13:21 — Martin Heralecký
– Martin Heralecký, Commented May 17, 2017 at 13:21

MAZux · Accepted Answer · 2019-07-13 20:43:05Z

4

You are passing entire image source to function deleteimg as $img. Just sent image name .Then use unlink(PATH TO YOUR IMAGE "/" IMAGE NAME). Like you may save the image in puplic/uploads then use unlink(public_path().'/uploads/'.$imageName);

edited Jul 13, 2019 at 20:43

MAZux

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answered May 17, 2017 at 13:29

Nithin John

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8 Comments

Karthiga Over a year ago

yeah thank you but how i get the image name alone in jquery

Nithin John Over a year ago

You can use the currrent $img as it is .Just explode the $img by "/" and get the last array element.

Karthiga Over a year ago

can you give me the code i doknow how to use explode function

Nithin John Over a year ago

$img = "aaa/bb/a.jpg"; $imgArray = explode('/',$img); $imageName = $imgArray[count($imgArray)-1]; echo $imageName;

Karthiga Over a year ago

by using explode('/',$img) it split the array now how i get the last element

|

Gaurav Gupta · Accepted Answer · 2017-05-17 13:11:06Z

0

try this

unlink(public_path().'/'.$img);

this work fine for me

answered May 17, 2017 at 13:11

Gaurav Gupta

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Comments

Sagar Gautam · Accepted Answer · 2017-05-17 13:21:26Z

0

This might work. Just send image path through ajax call. This will return true if file is deleted. And check your route as well in web.php file

use Illuminate\Support\Facades\Storage;

public function deleteimg($file_path){
      Storage::delete($file_path);
      return response()->json(array('success' => true));
}

answered May 17, 2017 at 13:21

Sagar Gautam

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2 Comments

Karthiga Over a year ago

it working I found whats the problem but i doknow how to get the solution when i return my $img variable it shows like this

Object {message: "http://birdys.app/uploads/products/images/50/11474…M-Unisex-Table-Covers-9731474522719404-1_mini.jpg"}

in my console window but when i try to remove that "birdys.app" it working correctly

Sagar Gautam Over a year ago

Any other problem than file delete ?

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