Count number of character occurrences in a string in PHP without use available function

Question

Sorry if this question already exists. I have a question can you help me. Only use strlen function and array. Can you make programming count number of character occurrences in a string with PHP (Character not repeat). Similar to create a new array_count_values function that available in php. Eg:

$input = 'lorem lis pum';
Output: 
l appeared 2 times;
o appeared 1 times;
r appeared 1 times;
...

This is my code when using available function array_count_values and it's worked.

$a = str_split($str, 1);
foreach (array_count_values($a) as $key => $value) {
    if ($key === ' ') {
        $key = '_';
    }
    echo $key.'appeared '.$value.' times<br>';
}

Thanks for read.

I'm curios to know why you need to create a paradigm that is already exist ? does there another approach you want to achieve ? and for that you need to create a new method for that? — hassan
– hassan, Commented May 22, 2017 at 8:55
@hassan I want to learn more about this. and maybe I will make a new method in the future. :)) — Mr D
– Mr D, Commented May 22, 2017 at 9:00

Decent Dabbler · Accepted Answer · 2017-05-22 09:06:09Z

3

This is one way to do it. I'm sure there's even more concise ways to do it.

$input = 'lorem lis pum';

for( $i = 0, $ilen = strlen( $input ), $result = array(); $i < $ilen; $i++ ) {
  $chr = $input[ $i ];
  // substituting the space with an underscore is not actually necessary
  if( $chr === ' ' ) {
    $chr = '_';
  }
  $result[ $chr ] = isset( $result[ $chr ] ) ? $result[ $chr ] + 1 : 1;
}

var_dump( $result );

^{You can view this example online.}

edited May 22, 2017 at 9:06

answered May 22, 2017 at 8:59

Decent Dabbler

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1 Comment

Your Common Sense Over a year ago

while(isset($input[$i++]))

Mlax Wong · Accepted Answer · 2017-05-22 09:06:54Z

You can try this, hope its help :)

<?php
$input = 'lorem lis pum';

function outputs($input)
{
    $input = str_replace(' ', '', $input);

    $characters = str_split($input);

    $outputs = [];

    foreach ($characters as $char)
    {
        if(!isset($outputs[$char])){
            $outputs[$char] = 1;
        } else {
            $outputs[$char] += 1;
        }
    }

    foreach ($outputs as $char => $number)
    {
        echo $char . ' appeared ' . $number . ' times;<br />';
    }
}

outputs($input);
?>

or simple version:

<?php
$input = 'lorem lis pum';

function outputs($input)
{
    //suggest remove all spaces first
    $input = str_replace(' ', '', $input);

    $chars = str_split($input);

    foreach (array_count_values($chars) as $key => $value)
    {
        echo $key. ' appeared '.$value.' times<br>';
    }
}

outputs($input);
?>

Timur · Accepted Answer · 2017-05-22 09:02:14Z

0

Try use function count_chars

foreach (count_chars($str, 1) as $key => $value) {
    echo chr($key).' appeared '.$value.' times<br>';
}

answered May 22, 2017 at 9:02

Timur

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1 Comment

Mr D Over a year ago

thanks @Timur but I don't want to use availiable function.

Adan Elahi · Accepted Answer · 2024-08-14 11:09:40Z

-1

you should try this...

if "strlen()" also not allowed then use another for loop to find the length



 $str = "hippopotamous";
    function countValue($str){
        $arr = [];
        $len = strlen($str);
        for($k = 0; $k<$len; $k++){
            $arr[$str[$k]] =0;
        }
        for($i=0; $i<$len; $i++){
                if($arr[$str[$i]]){
                    $arr[$str[$i]] +=1;
                }else{
                     $arr[$str[$i]] =1;
                }
        }
        return $arr;
    } 
    print_r(countValue($str));

answered Aug 14, 2024 at 11:09

Adan Elahi

1

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